Every day, a cyclist moving along a straight road parallel to the railway track, meets a train at a particular crossing. The cyclist and the train are travel in the same direction.. The cyclist travels with a speed of 10 kmph. One day, the cyclist comes late by 25 minutes and meets the train 5 km ahead of the crossing. What is the speed of the train?
a)22 kmph      b) 20kmph    c) 60kmph      d) 30kmph     e)45kmph

.........................................A.....................................LC...............  Normally

7.55am                         8,00 am

Let us assume they meet at 8 am every day at the level crossing.  Today the cyclist has started 25 minutes late and hence he will be at the level crossing only at 8.25 am.  Today the cyclist meets the train 5 km  from the level crossing.  that means the time now should be 7.55 am-- he travels at 10 km per hour and it will take 30 minutes for him to reach level crossing.  The train covers 5 km in 5  minutes.  So the speed of the train is 60 km per hour.

#### 1 comment:

1. Excellent post and wonderful blog, I really like this type of interesting articles.
_________________
Essay Writing